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14452132153 is a prime number
BaseRepresentation
bin11010111010110101…
…00000100100111001
31101022012020101021211
431131122200210321
5214044221212103
610350023203121
71021065045034
oct153532404471
941265211254
1014452132153
116146940878
122973ba64a1
1314941a41b4
149b156c01b
15598b9336d
hex35d6a0939

14452132153 has 2 divisors, whose sum is σ = 14452132154. Its totient is φ = 14452132152.

The previous prime is 14452132111. The next prime is 14452132181. The reversal of 14452132153 is 35123125441.

14452132153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13481996544 + 970135609 = 116112^2 + 31147^2 .

It is a cyclic number.

It is not a de Polignac number, because 14452132153 - 29 = 14452131641 is a prime.

It is not a weakly prime, because it can be changed into another prime (14452132193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7226066076 + 7226066077.

It is an arithmetic number, because the mean of its divisors is an integer number (7226066077).

Almost surely, 214452132153 is an apocalyptic number.

It is an amenable number.

14452132153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14452132153 is an equidigital number, since it uses as much as digits as its factorization.

14452132153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 14400, while the sum is 31.

Adding to 14452132153 its reverse (35123125441), we get a palindrome (49575257594).

The spelling of 14452132153 in words is "fourteen billion, four hundred fifty-two million, one hundred thirty-two thousand, one hundred fifty-three".