Base | Representation |
---|---|
bin | 1101001001001111111100… |
… | …1000101011111110011111 |
3 | 1220011122120002102211120011 |
4 | 3102103333020223332133 |
5 | 3343242310403413403 |
6 | 50423224321504051 |
7 | 3021106446616612 |
oct | 322237710537637 |
9 | 56148502384504 |
10 | 14452550451103 |
11 | 4672323a52766 |
12 | 1755001aa2027 |
13 | 80ab3c846c6b |
14 | 37d715986179 |
15 | 1a0e26030a6d |
hex | d24ff22bf9f |
14452550451103 has 2 divisors, whose sum is σ = 14452550451104. Its totient is φ = 14452550451102.
The previous prime is 14452550451067. The next prime is 14452550451179. The reversal of 14452550451103 is 30115405525441.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14452550451103 - 233 = 14443960516511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14452550451193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7226275225551 + 7226275225552.
It is an arithmetic number, because the mean of its divisors is an integer number (7226275225552).
Almost surely, 214452550451103 is an apocalyptic number.
14452550451103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14452550451103 is an equidigital number, since it uses as much as digits as its factorization.
14452550451103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 14452550451103 its reverse (30115405525441), we get a palindrome (44567955976544).
The spelling of 14452550451103 in words is "fourteen trillion, four hundred fifty-two billion, five hundred fifty million, four hundred fifty-one thousand, one hundred three".
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