Base | Representation |
---|---|
bin | 1000011010011101000… |
… | …0110110001111010111 |
3 | 111211002020202111102202 |
4 | 2012213100312033113 |
5 | 4332004233213221 |
6 | 150222324355115 |
7 | 13304560565441 |
oct | 2064720661727 |
9 | 454066674382 |
10 | 144540132311 |
11 | 56332155803 |
12 | 2401a245a9b |
13 | 1082637a613 |
14 | 6dd25c3491 |
15 | 3b5e5dad0b |
hex | 21a74363d7 |
144540132311 has 4 divisors (see below), whose sum is σ = 145050875112. Its totient is φ = 144029389512.
The previous prime is 144540132301. The next prime is 144540132323. The reversal of 144540132311 is 113231045441.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-144540132311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (144540132301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255370976 + ... + 255371541.
It is an arithmetic number, because the mean of its divisors is an integer number (36262718778).
Almost surely, 2144540132311 is an apocalyptic number.
144540132311 is a deficient number, since it is larger than the sum of its proper divisors (510742801).
144540132311 is an equidigital number, since it uses as much as digits as its factorization.
144540132311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 510742800.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 144540132311 its reverse (113231045441), we get a palindrome (257771177752).
The spelling of 144540132311 in words is "one hundred forty-four billion, five hundred forty million, one hundred thirty-two thousand, three hundred eleven".
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