Search a number
-
+
144540132311 = 283510742517
BaseRepresentation
bin1000011010011101000…
…0110110001111010111
3111211002020202111102202
42012213100312033113
54332004233213221
6150222324355115
713304560565441
oct2064720661727
9454066674382
10144540132311
1156332155803
122401a245a9b
131082637a613
146dd25c3491
153b5e5dad0b
hex21a74363d7

144540132311 has 4 divisors (see below), whose sum is σ = 145050875112. Its totient is φ = 144029389512.

The previous prime is 144540132301. The next prime is 144540132323. The reversal of 144540132311 is 113231045441.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-144540132311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (144540132301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255370976 + ... + 255371541.

It is an arithmetic number, because the mean of its divisors is an integer number (36262718778).

Almost surely, 2144540132311 is an apocalyptic number.

144540132311 is a deficient number, since it is larger than the sum of its proper divisors (510742801).

144540132311 is an equidigital number, since it uses as much as digits as its factorization.

144540132311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 510742800.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 144540132311 its reverse (113231045441), we get a palindrome (257771177752).

The spelling of 144540132311 in words is "one hundred forty-four billion, five hundred forty million, one hundred thirty-two thousand, three hundred eleven".

Divisors: 1 283 510742517 144540132311