Base | Representation |
---|---|
bin | 100000110111011000010111… |
… | …011101100101001101010100 |
3 | 200221210012022201212100222222 |
4 | 200313120113131211031110 |
5 | 122421144010042311012 |
6 | 1231230123455241512 |
7 | 42305621545506422 |
oct | 4067302735451524 |
9 | 627705281770888 |
10 | 144543223010132 |
11 | 42068489178591 |
12 | 14265540b19298 |
13 | 62864a137352b |
14 | 2799d020b6112 |
15 | 11a9d7aa07972 |
hex | 837617765354 |
144543223010132 has 12 divisors (see below), whose sum is σ = 254149458469536. Its totient is φ = 71929092018840.
The previous prime is 144543223010111. The next prime is 144543223010141. The reversal of 144543223010132 is 231010322345441.
144543223010132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 144543223010092 and 144543223010101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85629870608 + ... + 85629872295.
It is an arithmetic number, because the mean of its divisors is an integer number (21179121539128).
Almost surely, 2144543223010132 is an apocalyptic number.
It is an amenable number.
144543223010132 is a deficient number, since it is larger than the sum of its proper divisors (109606235459404).
144543223010132 is a wasteful number, since it uses less digits than its factorization.
144543223010132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171259743118 (or 171259743116 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 144543223010132 its reverse (231010322345441), we get a palindrome (375553545355573).
The spelling of 144543223010132 in words is "one hundred forty-four trillion, five hundred forty-three billion, two hundred twenty-three million, ten thousand, one hundred thirty-two".
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