Base | Representation |
---|---|
bin | 11010111011110010… |
… | …10111111100001001 |
3 | 1101022202110110011202 |
4 | 31131321113330021 |
5 | 214103304120431 |
6 | 10350512433545 |
7 | 1021223604152 |
oct | 153571277411 |
9 | 41282413152 |
10 | 14460223241 |
11 | 6150467822 |
12 | 29768488b5 |
13 | 1495a77c19 |
14 | 9b2676929 |
15 | 5997408cb |
hex | 35de57f09 |
14460223241 has 2 divisors, whose sum is σ = 14460223242. Its totient is φ = 14460223240.
The previous prime is 14460223213. The next prime is 14460223243. The reversal of 14460223241 is 14232206441.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11492697616 + 2967525625 = 107204^2 + 54475^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14460223241 is a prime.
Together with 14460223243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14460223243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7230111620 + 7230111621.
It is an arithmetic number, because the mean of its divisors is an integer number (7230111621).
Almost surely, 214460223241 is an apocalyptic number.
It is an amenable number.
14460223241 is a deficient number, since it is larger than the sum of its proper divisors (1).
14460223241 is an equidigital number, since it uses as much as digits as its factorization.
14460223241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 14460223241 its reverse (14232206441), we get a palindrome (28692429682).
The spelling of 14460223241 in words is "fourteen billion, four hundred sixty million, two hundred twenty-three thousand, two hundred forty-one".
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