144980000131 has 2 divisors, whose sum is σ = 144980000132. Its totient is φ = 144980000130.

The previous prime is 144980000129. The next prime is 144980000167. The reversal of 144980000131 is 131000089441.

144980000131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 144980000131 - 2¹ = 144980000129 is a prime.

It is a super-2 number, since 2×144980000131² (a number of 23 digits) contains 22 as substring.

Together with 144980000129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 144980000093 and 144980000102.

It is not a weakly prime, because it can be changed into another prime (144980000731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72490000065 + 72490000066.

It is an arithmetic number, because the mean of its divisors is an integer number (72490000066).

Almost surely, 2^144980000131 is an apocalyptic number.

144980000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

144980000131 is an equidigital number, since it uses as much as digits as its factorization.

144980000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 31.

Adding to 144980000131 its reverse (131000089441), we get a palindrome (275980089572).

The spelling of 144980000131 in words is "one hundred forty-four billion, nine hundred eighty million, one hundred thirty-one", and thus it is an aban number.