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145004113 is a prime number
BaseRepresentation
bin10001010010010…
…01011001010001
3101002211222020201
420221021121101
5244110112423
622215535201
73410341342
oct1051113121
9332758221
10145004113
117493a811
124068a501
132406cc67
14153880c9
15cae42ad
hex8a49651

145004113 has 2 divisors, whose sum is σ = 145004114. Its totient is φ = 145004112.

The previous prime is 145004077. The next prime is 145004129. The reversal of 145004113 is 311400541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144552529 + 451584 = 12023^2 + 672^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145004113 is a prime.

It is not a weakly prime, because it can be changed into another prime (145004513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72502056 + 72502057.

It is an arithmetic number, because the mean of its divisors is an integer number (72502057).

Almost surely, 2145004113 is an apocalyptic number.

It is an amenable number.

145004113 is a deficient number, since it is larger than the sum of its proper divisors (1).

145004113 is an equidigital number, since it uses as much as digits as its factorization.

145004113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 145004113 is about 12041.7653606105. The cubic root of 145004113 is about 525.3637545602.

Adding to 145004113 its reverse (311400541), we get a palindrome (456404654).

The spelling of 145004113 in words is "one hundred forty-five million, four thousand, one hundred thirteen".