145011435421 has 4 divisors (see below), whose sum is σ = 145302040000. Its totient is φ = 144720830844.

The previous prime is 145011435397. The next prime is 145011435433. The reversal of 145011435421 is 124534110541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 124534110541 = 89 ⋅1399259669.

It is a cyclic number.

It is not a de Polignac number, because 145011435421 - 2⁵ = 145011435389 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145011435451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 145301541 + ... + 145302538.

It is an arithmetic number, because the mean of its divisors is an integer number (36325510000).

Almost surely, 2^145011435421 is an apocalyptic number.

It is an amenable number.

145011435421 is a deficient number, since it is larger than the sum of its proper divisors (290604579).

145011435421 is an equidigital number, since it uses as much as digits as its factorization.

145011435421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 290604578.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 145011435421 its reverse (124534110541), we get a palindrome (269545545962).

The spelling of 145011435421 in words is "one hundred forty-five billion, eleven million, four hundred thirty-five thousand, four hundred twenty-one".