Base | Representation |
---|---|
bin | 1000011100001101011… |
… | …1001001000100001101 |
3 | 111212022002210201011021 |
4 | 2013003113021010031 |
5 | 4333440423404313 |
6 | 150341204354141 |
7 | 13322343534505 |
oct | 2070327110415 |
9 | 455262721137 |
10 | 145011544333 |
11 | 56554266617 |
12 | 241300a5951 |
13 | 1089cc33346 |
14 | 7039056a05 |
15 | 3b8aba878d |
hex | 21c35c910d |
145011544333 has 2 divisors, whose sum is σ = 145011544334. Its totient is φ = 145011544332.
The previous prime is 145011544189. The next prime is 145011544361. The reversal of 145011544333 is 333445110541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123368132644 + 21643411689 = 351238^2 + 147117^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-145011544333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145011944333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72505772166 + 72505772167.
It is an arithmetic number, because the mean of its divisors is an integer number (72505772167).
Almost surely, 2145011544333 is an apocalyptic number.
It is an amenable number.
145011544333 is a deficient number, since it is larger than the sum of its proper divisors (1).
145011544333 is an equidigital number, since it uses as much as digits as its factorization.
145011544333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 145011544333 its reverse (333445110541), we get a palindrome (478456654874).
The spelling of 145011544333 in words is "one hundred forty-five billion, eleven million, five hundred forty-four thousand, three hundred thirty-three".
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