14501232131 has 4 divisors (see below), whose sum is σ = 14514500592. Its totient is φ = 14487963672.

The previous prime is 14501232127. The next prime is 14501232191. The reversal of 14501232131 is 13123210541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13123210541 = 7 ⋅1874744363.

It is a cyclic number.

It is not a de Polignac number, because 14501232131 - 2² = 14501232127 is a prime.

It is a super-2 number, since 2×14501232131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14501232097 and 14501232106.

It is not an unprimeable number, because it can be changed into a prime (14501232121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6632591 + ... + 6634776.

It is an arithmetic number, because the mean of its divisors is an integer number (3628625148).

Almost surely, 2^14501232131 is an apocalyptic number.

14501232131 is a deficient number, since it is larger than the sum of its proper divisors (13268461).

14501232131 is a wasteful number, since it uses less digits than its factorization.

14501232131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13268460.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 14501232131 its reverse (13123210541), we get a palindrome (27624442672).

The spelling of 14501232131 in words is "fourteen billion, five hundred one million, two hundred thirty-two thousand, one hundred thirty-one".