145014021403 has 4 divisors (see below), whose sum is σ = 146643392520. Its totient is φ = 143384650288.

The previous prime is 145014021389. The next prime is 145014021409. The reversal of 145014021403 is 304120410541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304120410541 = 43 ⋅7072567687.

It is a cyclic number.

It is not a de Polignac number, because 145014021403 - 2²¹ = 145011924251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145014021409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 814685425 + ... + 814685602.

It is an arithmetic number, because the mean of its divisors is an integer number (36660848130).

Almost surely, 2^145014021403 is an apocalyptic number.

145014021403 is a deficient number, since it is larger than the sum of its proper divisors (1629371117).

145014021403 is an equidigital number, since it uses as much as digits as its factorization.

145014021403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1629371116.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 145014021403 its reverse (304120410541), we get a palindrome (449134431944).

The spelling of 145014021403 in words is "one hundred forty-five billion, fourteen million, twenty-one thousand, four hundred three".