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14502230513423 is a prime number
BaseRepresentation
bin1101001100001001000001…
…0011000101011100001111
31220100101210101020111012022
43103002100103011130033
53400101032002412143
650502122134000355
73024515535313502
oct323022023053417
956311711214168
1014502230513423
1146913a8063904
1217627677a60bb
13812729227c43
14381ca99d3139
151a2382779268
hexd30904c570f

14502230513423 has 2 divisors, whose sum is σ = 14502230513424. Its totient is φ = 14502230513422.

The previous prime is 14502230513413. The next prime is 14502230513429. The reversal of 14502230513423 is 32431503220541.

It is a strong prime.

It is an emirp because it is prime and its reverse (32431503220541) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14502230513423 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14502230513429) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7251115256711 + 7251115256712.

It is an arithmetic number, because the mean of its divisors is an integer number (7251115256712).

Almost surely, 214502230513423 is an apocalyptic number.

14502230513423 is a deficient number, since it is larger than the sum of its proper divisors (1).

14502230513423 is an equidigital number, since it uses as much as digits as its factorization.

14502230513423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 14502230513423 its reverse (32431503220541), we get a palindrome (46933733733964).

The spelling of 14502230513423 in words is "fourteen trillion, five hundred two billion, two hundred thirty million, five hundred thirteen thousand, four hundred twenty-three".