14502232113634 has 4 divisors (see below), whose sum is σ = 21753348170454. Its totient is φ = 7251116056816.

The previous prime is 14502232113631. The next prime is 14502232113647. The reversal of 14502232113634 is 43631123220541.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12912501999609 + 1589730114025 = 3593397^2 + 1260845^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14502232113593 and 14502232113602.

It is not an unprimeable number, because it can be changed into a prime (14502232113631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3625558028407 + ... + 3625558028410.

Almost surely, 2^{14502232113634} is an apocalyptic number.

14502232113634 is a deficient number, since it is larger than the sum of its proper divisors (7251116056820).

14502232113634 is an equidigital number, since it uses as much as digits as its factorization.

14502232113634 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7251116056819.

The product of its (nonzero) digits is 103680, while the sum is 37.

The spelling of 14502232113634 in words is "fourteen trillion, five hundred two billion, two hundred thirty-two million, one hundred thirteen thousand, six hundred thirty-four".