Base | Representation |
---|---|
bin | 1000011100010000001… |
… | …0111110000010110011 |
3 | 111212022220102102100211 |
4 | 2013010002332002303 |
5 | 4334001344033043 |
6 | 150342254524551 |
7 | 13322543305624 |
oct | 2070402760263 |
9 | 455286372324 |
10 | 145023033523 |
11 | 5655a7a3615 |
12 | 24133b06757 |
13 | 108a2426994 |
14 | 703a7a7a4b |
15 | 3b8bbc7a9d |
hex | 21c40be0b3 |
145023033523 has 2 divisors, whose sum is σ = 145023033524. Its totient is φ = 145023033522.
The previous prime is 145023033521. The next prime is 145023033557. The reversal of 145023033523 is 325330320541.
It is a weak prime.
It is an emirp because it is prime and its reverse (325330320541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145023033523 - 21 = 145023033521 is a prime.
Together with 145023033521, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (145023033521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72511516761 + 72511516762.
It is an arithmetic number, because the mean of its divisors is an integer number (72511516762).
Almost surely, 2145023033523 is an apocalyptic number.
145023033523 is a deficient number, since it is larger than the sum of its proper divisors (1).
145023033523 is an equidigital number, since it uses as much as digits as its factorization.
145023033523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 31.
The spelling of 145023033523 in words is "one hundred forty-five billion, twenty-three million, thirty-three thousand, five hundred twenty-three".
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