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145025455111 = 433577580471
BaseRepresentation
bin1000011100010000110…
…0001101010000000111
3111212100001222110011021
42013010030031100013
54334003004030421
6150342422452011
713322603012635
oct2070414152007
9455301873137
10145025455111
11565610a7a29
1224134894007
13108a2a93c84
14703ac38355
153b8c005341
hex21c430d407

145025455111 has 8 divisors (see below), whose sum is σ = 145612562144. Its totient is φ = 144439511040.

The previous prime is 145025455109. The next prime is 145025455117. The reversal of 145025455111 is 111554520541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145025455111 - 21 = 145025455109 is a prime.

It is a super-4 number, since 4×1450254551114 (a number of 46 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145025455117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40395 + ... + 540076.

It is an arithmetic number, because the mean of its divisors is an integer number (18201570268).

Almost surely, 2145025455111 is an apocalyptic number.

145025455111 is a deficient number, since it is larger than the sum of its proper divisors (587107033).

145025455111 is an equidigital number, since it uses as much as digits as its factorization.

145025455111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 581481.

The product of its (nonzero) digits is 20000, while the sum is 34.

Adding to 145025455111 its reverse (111554520541), we get a palindrome (256579975652).

The spelling of 145025455111 in words is "one hundred forty-five billion, twenty-five million, four hundred fifty-five thousand, one hundred eleven".

Divisors: 1 433 577 249841 580471 251343943 334931767 145025455111