145034464213 has 4 divisors (see below), whose sum is σ = 145573626060. Its totient is φ = 144495302368.

The previous prime is 145034464199. The next prime is 145034464217. The reversal of 145034464213 is 312464430541.

145034464213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 312464430541 = 75217 ⋅4154173.

It can be written as a sum of positive squares in 2 ways, for example, as 58272994404 + 86761469809 = 241398^2 + 294553^2 .

It is a cyclic number.

It is not a de Polignac number, because 145034464213 - 2¹⁷ = 145034333141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (145034464217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269580520 + ... + 269581057.

It is an arithmetic number, because the mean of its divisors is an integer number (36393406515).

Almost surely, 2^145034464213 is an apocalyptic number.

It is an amenable number.

145034464213 is a deficient number, since it is larger than the sum of its proper divisors (539161847).

145034464213 is an equidigital number, since it uses as much as digits as its factorization.

145034464213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 539161846.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 145034464213 its reverse (312464430541), we get a palindrome (457498894754).

The spelling of 145034464213 in words is "one hundred forty-five billion, thirty-four million, four hundred sixty-four thousand, two hundred thirteen".