Base | Representation |
---|---|
bin | 1000011100010011001… |
… | …0101110011000101101 |
3 | 111212100202222102220021 |
4 | 2013010302232120231 |
5 | 4334013100133201 |
6 | 150343423122141 |
7 | 13323054565543 |
oct | 2070462563055 |
9 | 455322872807 |
10 | 145035552301 |
11 | 56566874112 |
12 | 24138143351 |
13 | 108a4bbab43 |
14 | 703c305d93 |
15 | 3b8cd4bea1 |
hex | 21c4cae62d |
145035552301 has 2 divisors, whose sum is σ = 145035552302. Its totient is φ = 145035552300.
The previous prime is 145035552239. The next prime is 145035552323. The reversal of 145035552301 is 103255530541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131776260100 + 13259292201 = 363010^2 + 115149^2 .
It is a cyclic number.
It is not a de Polignac number, because 145035552301 - 217 = 145035421229 is a prime.
It is a super-2 number, since 2×1450355523012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145035552371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72517776150 + 72517776151.
It is an arithmetic number, because the mean of its divisors is an integer number (72517776151).
Almost surely, 2145035552301 is an apocalyptic number.
It is an amenable number.
145035552301 is a deficient number, since it is larger than the sum of its proper divisors (1).
145035552301 is an equidigital number, since it uses as much as digits as its factorization.
145035552301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 34.
The spelling of 145035552301 in words is "one hundred forty-five billion, thirty-five million, five hundred fifty-two thousand, three hundred one".
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