14503801133 has 2 divisors, whose sum is σ = 14503801134. Its totient is φ = 14503801132.

The previous prime is 14503801099. The next prime is 14503801153. The reversal of 14503801133 is 33110830541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10509940324 + 3993860809 = 102518^2 + 63197^2 .

It is a cyclic number.

It is not a de Polignac number, because 14503801133 - 2¹² = 14503797037 is a prime.

It is a super-2 number, since 2×14503801133² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14503801096 and 14503801105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14503801153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7251900566 + 7251900567.

It is an arithmetic number, because the mean of its divisors is an integer number (7251900567).

Almost surely, 2^14503801133 is an apocalyptic number.

It is an amenable number.

14503801133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14503801133 is an equidigital number, since it uses as much as digits as its factorization.

14503801133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 29.

The spelling of 14503801133 in words is "fourteen billion, five hundred three million, eight hundred one thousand, one hundred thirty-three".