Base | Representation |
---|---|
bin | 11011000001010100… |
… | …10101100101011001 |
3 | 1101102222202022001222 |
4 | 31200222111211121 |
5 | 214202143104311 |
6 | 10355251021425 |
7 | 1022326114412 |
oct | 154052254531 |
9 | 41388668058 |
10 | 14506613081 |
11 | 6174672134 |
12 | 298a29a875 |
13 | 14a256b02c |
14 | 9b88b0809 |
15 | 59d855adb |
hex | 360a95959 |
14506613081 has 2 divisors, whose sum is σ = 14506613082. Its totient is φ = 14506613080.
The previous prime is 14506613053. The next prime is 14506613083. The reversal of 14506613081 is 18031660541.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13933441600 + 573171481 = 118040^2 + 23941^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14506613081 is a prime.
It is a super-2 number, since 2×145066130812 (a number of 21 digits) contains 22 as substring.
Together with 14506613083, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14506613083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7253306540 + 7253306541.
It is an arithmetic number, because the mean of its divisors is an integer number (7253306541).
Almost surely, 214506613081 is an apocalyptic number.
It is an amenable number.
14506613081 is a deficient number, since it is larger than the sum of its proper divisors (1).
14506613081 is an equidigital number, since it uses as much as digits as its factorization.
14506613081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 35.
The spelling of 14506613081 in words is "fourteen billion, five hundred six million, six hundred thirteen thousand, eighty-one".
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