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145070763113 is a prime number
BaseRepresentation
bin1000011100011011100…
…1000010110001101001
3111212110020020100001102
42013012321002301221
54334101103404423
6150351121531145
713323663066143
oct2070671026151
9455406210042
10145070763113
1156584733561
1224147aa3ab5
13108ac298843
147042c6dc93
153b90ea4c28
hex21c6e42c69

145070763113 has 2 divisors, whose sum is σ = 145070763114. Its totient is φ = 145070763112.

The previous prime is 145070763029. The next prime is 145070763127. The reversal of 145070763113 is 311367070541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133029431824 + 12041331289 = 364732^2 + 109733^2 .

It is a cyclic number.

It is not a de Polignac number, because 145070763113 - 232 = 140775795817 is a prime.

It is a super-2 number, since 2×1450707631132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (145070763163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72535381556 + 72535381557.

It is an arithmetic number, because the mean of its divisors is an integer number (72535381557).

Almost surely, 2145070763113 is an apocalyptic number.

It is an amenable number.

145070763113 is a deficient number, since it is larger than the sum of its proper divisors (1).

145070763113 is an equidigital number, since it uses as much as digits as its factorization.

145070763113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52920, while the sum is 38.

The spelling of 145070763113 in words is "one hundred forty-five billion, seventy million, seven hundred sixty-three thousand, one hundred thirteen".