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145112201441 = 3131408732911
BaseRepresentation
bin1000011100100101011…
…1000111100011100001
3111212120010012121202022
42013021113013203201
54334142210421231
6150355202031225
713325005234454
oct2071127074341
9455503177668
10145112201441
11565a6066809
1224159948515
13108b7a46c6c
14704857949b
153b9493cc7b
hex21c95c78e1

145112201441 has 8 divisors (see below), whose sum is σ = 145590576384. Its totient is φ = 144633921120.

The previous prime is 145112201419. The next prime is 145112201477. The reversal of 145112201441 is 144102211541.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-145112201441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 145112201441.

It is not an unprimeable number, because it can be changed into a prime (145112201141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4392776 + ... + 4425686.

It is an arithmetic number, because the mean of its divisors is an integer number (18198822048).

Almost surely, 2145112201441 is an apocalyptic number.

It is an amenable number.

145112201441 is a deficient number, since it is larger than the sum of its proper divisors (478374943).

145112201441 is a wasteful number, since it uses less digits than its factorization.

145112201441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47311.

The product of its (nonzero) digits is 1280, while the sum is 26.

Adding to 145112201441 its reverse (144102211541), we get a palindrome (289214412982).

The spelling of 145112201441 in words is "one hundred forty-five billion, one hundred twelve million, two hundred one thousand, four hundred forty-one".

Divisors: 1 313 14087 32911 4409231 10301143 463617257 145112201441