Base | Representation |
---|---|
bin | 1000011100100101111… |
… | …0000111000000111011 |
3 | 111212120020122201212120 |
4 | 2013021132013000323 |
5 | 4334143143043420 |
6 | 150355305212323 |
7 | 13325026640052 |
oct | 2071136070073 |
9 | 455506581776 |
10 | 145114034235 |
11 | 565a70a8815 |
12 | 2415a4910a3 |
13 | 108b8239261 |
14 | 70488d5399 |
15 | 3b94ba0d40 |
hex | 21c978703b |
145114034235 has 64 divisors (see below), whose sum is σ = 242694144000. Its totient is φ = 73947686400.
The previous prime is 145114034213. The next prime is 145114034243. The reversal of 145114034235 is 532430411541.
It is not a de Polignac number, because 145114034235 - 28 = 145114033979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145114034196 and 145114034205.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 54573336 + ... + 54575994.
It is an arithmetic number, because the mean of its divisors is an integer number (3792096000).
Almost surely, 2145114034235 is an apocalyptic number.
145114034235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
145114034235 is a deficient number, since it is larger than the sum of its proper divisors (97580109765).
145114034235 is a wasteful number, since it uses less digits than its factorization.
145114034235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3956.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 145114034235 its reverse (532430411541), we get a palindrome (677544445776).
The spelling of 145114034235 in words is "one hundred forty-five billion, one hundred fourteen million, thirty-four thousand, two hundred thirty-five".
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