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14512840604813 is a prime number
BaseRepresentation
bin1101001100110000100010…
…1101010111110010001101
31220101102011210222222101002
43103030020231113302031
53400234244143323223
650511035033030045
73025342501514525
oct323141055276215
956342153888332
1014512840604813
114695952199581
121764828b55325
1381372a435325
143825d4ba8685
151a27a3e99e28
hexd3308b57c8d

14512840604813 has 2 divisors, whose sum is σ = 14512840604814. Its totient is φ = 14512840604812.

The previous prime is 14512840604707. The next prime is 14512840604851. The reversal of 14512840604813 is 31840604821541.

14512840604813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10925384897449 + 3587455707364 = 3305357^2 + 1894058^2 .

It is a cyclic number.

It is not a de Polignac number, because 14512840604813 - 212 = 14512840600717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14512840604863) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7256420302406 + 7256420302407.

It is an arithmetic number, because the mean of its divisors is an integer number (7256420302407).

Almost surely, 214512840604813 is an apocalyptic number.

It is an amenable number.

14512840604813 is a deficient number, since it is larger than the sum of its proper divisors (1).

14512840604813 is an equidigital number, since it uses as much as digits as its factorization.

14512840604813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 737280, while the sum is 47.

The spelling of 14512840604813 in words is "fourteen trillion, five hundred twelve billion, eight hundred forty million, six hundred four thousand, eight hundred thirteen".