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14514134431 is a prime number
BaseRepresentation
bin11011000010001110…
…00001110110011111
31101110111220102102111
431201013001312133
5214211104300211
610400120134451
71022450051506
oct154107016637
941414812374
1014514134431
11617893a025
122990907427
1314a3ca2634
149b98ab83d
1559e33e421
hex3611c1d9f

14514134431 has 2 divisors, whose sum is σ = 14514134432. Its totient is φ = 14514134430.

The previous prime is 14514134413. The next prime is 14514134471. The reversal of 14514134431 is 13443141541.

Together with previous prime (14514134413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14514134431 - 25 = 14514134399 is a prime.

It is a super-2 number, since 2×145141344312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14514134393 and 14514134402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14514134471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7257067215 + 7257067216.

It is an arithmetic number, because the mean of its divisors is an integer number (7257067216).

Almost surely, 214514134431 is an apocalyptic number.

14514134431 is a deficient number, since it is larger than the sum of its proper divisors (1).

14514134431 is an equidigital number, since it uses as much as digits as its factorization.

14514134431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11520, while the sum is 31.

Adding to 14514134431 its reverse (13443141541), we get a palindrome (27957275972).

The spelling of 14514134431 in words is "fourteen billion, five hundred fourteen million, one hundred thirty-four thousand, four hundred thirty-one".