Base | Representation |
---|---|
bin | 1000011100111011010… |
… | …1010100110100001001 |
3 | 111212210111221210010211 |
4 | 2013032311110310021 |
5 | 4334334211144103 |
6 | 150412241441121 |
7 | 13330201454623 |
oct | 2071665246411 |
9 | 455714853124 |
10 | 145204006153 |
11 | 5664296aa78 |
12 | 241846401a1 |
13 | 10900a7b48b |
14 | 7056835c13 |
15 | 3b9ca2436d |
hex | 21ced54d09 |
145204006153 has 4 divisors (see below), whose sum is σ = 145213500160. Its totient is φ = 145194512148.
The previous prime is 145204006151. The next prime is 145204006183. The reversal of 145204006153 is 351600402541.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 145204006153 - 21 = 145204006151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145204006151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4724025 + ... + 4754662.
It is an arithmetic number, because the mean of its divisors is an integer number (36303375040).
Almost surely, 2145204006153 is an apocalyptic number.
It is an amenable number.
145204006153 is a deficient number, since it is larger than the sum of its proper divisors (9494007).
145204006153 is an equidigital number, since it uses as much as digits as its factorization.
145204006153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9494006.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 145204006153 its reverse (351600402541), we get a palindrome (496804408694).
The spelling of 145204006153 in words is "one hundred forty-five billion, two hundred four million, six thousand, one hundred fifty-three".
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