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145211113 = 151961663
BaseRepresentation
bin10001010011110…
…11111011101001
3101010020111012101
420221323323221
5244133223423
622224213401
73412163005
oct1051737351
9333214171
10145211113
1174a71293
124076a261
1324113248
14153dd705
15cb357ad
hex8a7bee9

145211113 has 4 divisors (see below), whose sum is σ = 146172928. Its totient is φ = 144249300.

The previous prime is 145211111. The next prime is 145211119. The reversal of 145211113 is 311112541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145211113 - 21 = 145211111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145211111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 480681 + ... + 480982.

It is an arithmetic number, because the mean of its divisors is an integer number (36543232).

Almost surely, 2145211113 is an apocalyptic number.

It is an amenable number.

145211113 is a deficient number, since it is larger than the sum of its proper divisors (961815).

145211113 is an equidigital number, since it uses as much as digits as its factorization.

145211113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 961814.

The product of its digits is 120, while the sum is 19.

The square root of 145211113 is about 12050.3573805925. The cubic root of 145211113 is about 525.6136292874.

Adding to 145211113 its reverse (311112541), we get a palindrome (456323654).

The spelling of 145211113 in words is "one hundred forty-five million, two hundred eleven thousand, one hundred thirteen".

Divisors: 1 151 961663 145211113