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145215247 is a prime number
BaseRepresentation
bin10001010011111…
…00111100001111
3101010020200212111
420221330330033
5244133341442
622224244451
73412211032
oct1051747417
9333220774
10145215247
1174a74401
1240770727
13241150a8
1415401019
15cb36b17
hex8a7cf0f

145215247 has 2 divisors, whose sum is σ = 145215248. Its totient is φ = 145215246.

The previous prime is 145215221. The next prime is 145215277. The reversal of 145215247 is 742512541.

It is a weak prime.

It is an emirp because it is prime and its reverse (742512541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 145215247 - 211 = 145213199 is a prime.

It is a super-2 number, since 2×1452152472 = 42174935922542018, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145215277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72607623 + 72607624.

It is an arithmetic number, because the mean of its divisors is an integer number (72607624).

Almost surely, 2145215247 is an apocalyptic number.

145215247 is a deficient number, since it is larger than the sum of its proper divisors (1).

145215247 is an equidigital number, since it uses as much as digits as its factorization.

145215247 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11200, while the sum is 31.

The square root of 145215247 is about 12050.5289095541. The cubic root of 145215247 is about 525.6186171199.

Adding to 145215247 its reverse (742512541), we get a palindrome (887727788).

The spelling of 145215247 in words is "one hundred forty-five million, two hundred fifteen thousand, two hundred forty-seven".