145232300042041 has 2 divisors, whose sum is σ = 145232300042042. Its totient is φ = 145232300042040.

The previous prime is 145232300041991. The next prime is 145232300042057. The reversal of 145232300042041 is 140240003232541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130933094760000 + 14299205282041 = 11442600^2 + 3781429^2 .

It is a cyclic number.

It is not a de Polignac number, because 145232300042041 - 2¹⁷ = 145232299910969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 145232300041994 and 145232300042012.

It is not a weakly prime, because it can be changed into another prime (145232300082041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72616150021020 + 72616150021021.

It is an arithmetic number, because the mean of its divisors is an integer number (72616150021021).

Almost surely, 2^{145232300042041} is an apocalyptic number.

It is an amenable number.

145232300042041 is a deficient number, since it is larger than the sum of its proper divisors (1).

145232300042041 is an equidigital number, since it uses as much as digits as its factorization.

145232300042041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 145232300042041 its reverse (140240003232541), we get a palindrome (285472303274582).

The spelling of 145232300042041 in words is "one hundred forty-five trillion, two hundred thirty-two billion, three hundred million, forty-two thousand, forty-one".