Base | Representation |
---|---|
bin | 10101001000111011110… |
… | …010011001011011000111 |
3 | 12010212200022010110021222 |
4 | 111020323302121123013 |
5 | 142300113203410002 |
6 | 3031210113430555 |
7 | 206645211242051 |
oct | 25107362313307 |
9 | 5125608113258 |
10 | 1452702013127 |
11 | 5100a6461842 |
12 | 1b5662b6b45b |
13 | a6cb23b6721 |
14 | 5044db348d1 |
15 | 27bc4d361a2 |
hex | 1523bc996c7 |
1452702013127 has 4 divisors (see below), whose sum is σ = 1491964229736. Its totient is φ = 1413439796520.
The previous prime is 1452702013111. The next prime is 1452702013163. The reversal of 1452702013127 is 7213102072541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1452702013127 - 24 = 1452702013111 is a prime.
It is a super-2 number, since 2×14527020131272 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1452702013627) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19631108249 + ... + 19631108322.
It is an arithmetic number, because the mean of its divisors is an integer number (372991057434).
Almost surely, 21452702013127 is an apocalyptic number.
1452702013127 is a deficient number, since it is larger than the sum of its proper divisors (39262216609).
1452702013127 is an equidigital number, since it uses as much as digits as its factorization.
1452702013127 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39262216608.
The product of its (nonzero) digits is 23520, while the sum is 35.
Adding to 1452702013127 its reverse (7213102072541), we get a palindrome (8665804085668).
The spelling of 1452702013127 in words is "one trillion, four hundred fifty-two billion, seven hundred two million, thirteen thousand, one hundred twenty-seven".
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