Base | Representation |
---|---|
bin | 1101001101101001011000… |
… | …1111010110010001001111 |
3 | 1220102212120021020121112011 |
4 | 3103122112033112101033 |
5 | 3401012022100011342 |
6 | 50522041134522051 |
7 | 3026422601321566 |
oct | 323322617262117 |
9 | 56385507217464 |
10 | 14528100000847 |
11 | 46a1372781684 |
12 | 1767787366327 |
13 | 814cbc933754 |
14 | 383241632bdd |
15 | 1a2d9894c717 |
hex | d36963d644f |
14528100000847 has 2 divisors, whose sum is σ = 14528100000848. Its totient is φ = 14528100000846.
The previous prime is 14528100000839. The next prime is 14528100000923. The reversal of 14528100000847 is 74800000182541.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14528100000847 - 23 = 14528100000839 is a prime.
It is a super-3 number, since 3×145281000008473 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14528100000047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7264050000423 + 7264050000424.
It is an arithmetic number, because the mean of its divisors is an integer number (7264050000424).
Almost surely, 214528100000847 is an apocalyptic number.
14528100000847 is a deficient number, since it is larger than the sum of its proper divisors (1).
14528100000847 is an equidigital number, since it uses as much as digits as its factorization.
14528100000847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 71680, while the sum is 40.
The spelling of 14528100000847 in words is "fourteen trillion, five hundred twenty-eight billion, one hundred million, eight hundred forty-seven", and thus it is an aban number.
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