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14529665473 is a prime number
BaseRepresentation
bin11011000100000100…
…10001100111000001
31101111121010111000021
431202002101213001
5214224043243343
610401433053441
71023026055511
oct154202214701
941447114007
1014529665473
1161866877a4
122995b57281
1314a727c8bb
149bb991841
155a08ab0ed
hex3620919c1

14529665473 has 2 divisors, whose sum is σ = 14529665474. Its totient is φ = 14529665472.

The previous prime is 14529665441. The next prime is 14529665489. The reversal of 14529665473 is 37456692541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14526998784 + 2666689 = 120528^2 + 1633^2 .

It is a cyclic number.

It is not a de Polignac number, because 14529665473 - 25 = 14529665441 is a prime.

It is a super-2 number, since 2×145296654732 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14529665473.

It is not a weakly prime, because it can be changed into another prime (14529665273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7264832736 + 7264832737.

It is an arithmetic number, because the mean of its divisors is an integer number (7264832737).

Almost surely, 214529665473 is an apocalyptic number.

It is an amenable number.

14529665473 is a deficient number, since it is larger than the sum of its proper divisors (1).

14529665473 is an equidigital number, since it uses as much as digits as its factorization.

14529665473 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5443200, while the sum is 52.

The spelling of 14529665473 in words is "fourteen billion, five hundred twenty-nine million, six hundred sixty-five thousand, four hundred seventy-three".