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145300254317 is a prime number
BaseRepresentation
bin1000011101010010010…
…0011110111001101101
3111220001020001200210122
42013110210132321231
54340033331114232
6150430000414325
713332450532541
oct2072444367155
9456036050718
10145300254317
1156692229709
12241b09173a5
13109179aa35a
14706552ba21
153ba61d7312
hex21d491ee6d

145300254317 has 2 divisors, whose sum is σ = 145300254318. Its totient is φ = 145300254316.

The previous prime is 145300254293. The next prime is 145300254347. The reversal of 145300254317 is 713452003541.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106715902276 + 38584352041 = 326674^2 + 196429^2 .

It is a cyclic number.

It is not a de Polignac number, because 145300254317 - 28 = 145300254061 is a prime.

It is a super-2 number, since 2×1453002543172 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (145300254347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72650127158 + 72650127159.

It is an arithmetic number, because the mean of its divisors is an integer number (72650127159).

Almost surely, 2145300254317 is an apocalyptic number.

It is an amenable number.

145300254317 is a deficient number, since it is larger than the sum of its proper divisors (1).

145300254317 is an equidigital number, since it uses as much as digits as its factorization.

145300254317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 145300254317 its reverse (713452003541), we get a palindrome (858752257858).

The spelling of 145300254317 in words is "one hundred forty-five billion, three hundred million, two hundred fifty-four thousand, three hundred seventeen".