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14530040401 = 23631740887
BaseRepresentation
bin11011000100000111…
…01101001001010001
31101111121211112022111
431202003231021101
5214224142243101
610401445105321
71023032206552
oct154203551121
941447745274
1014530040401
116186913458
1229960b8241
1314a7381456
149bba4c329
155a0932251
hex3620ed251

14530040401 has 4 divisors (see below), whose sum is σ = 15161781312. Its totient is φ = 13898299492.

The previous prime is 14530040353. The next prime is 14530040419. The reversal of 14530040401 is 10404003541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10404003541 = 72823142867.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14530040401 is a prime.

It is a super-2 number, since 2×145300404012 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14530040501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315870421 + ... + 315870466.

It is an arithmetic number, because the mean of its divisors is an integer number (3790445328).

Almost surely, 214530040401 is an apocalyptic number.

It is an amenable number.

14530040401 is a deficient number, since it is larger than the sum of its proper divisors (631740911).

14530040401 is an equidigital number, since it uses as much as digits as its factorization.

14530040401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 631740910.

The product of its (nonzero) digits is 960, while the sum is 22.

Adding to 14530040401 its reverse (10404003541), we get a palindrome (24934043942).

The spelling of 14530040401 in words is "fourteen billion, five hundred thirty million, forty thousand, four hundred one".

Divisors: 1 23 631740887 14530040401