Base | Representation |
---|---|
bin | 1101001101110001101000… |
… | …0101111000101101101111 |
3 | 1220110002021102201112221011 |
4 | 3103130122011320231233 |
5 | 3401031034400104012 |
6 | 50523044440050051 |
7 | 3026531452055305 |
oct | 323343205705557 |
9 | 56402242645834 |
10 | 14530312113007 |
11 | 46a22a8424249 |
12 | 17680a4163927 |
13 | 815283016162 |
14 | 3833b1344275 |
15 | 1a2e77c5d1a7 |
hex | d371a178b6f |
14530312113007 has 2 divisors, whose sum is σ = 14530312113008. Its totient is φ = 14530312113006.
The previous prime is 14530312112971. The next prime is 14530312113017. The reversal of 14530312113007 is 70031121303541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14530312113007 - 231 = 14528164629359 is a prime.
It is a super-2 number, since 2×145303121130072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14530312113007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14530312113017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265156056503 + 7265156056504.
It is an arithmetic number, because the mean of its divisors is an integer number (7265156056504).
Almost surely, 214530312113007 is an apocalyptic number.
14530312113007 is a deficient number, since it is larger than the sum of its proper divisors (1).
14530312113007 is an equidigital number, since it uses as much as digits as its factorization.
14530312113007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 14530312113007 its reverse (70031121303541), we get a palindrome (84561433416548).
The spelling of 14530312113007 in words is "fourteen trillion, five hundred thirty billion, three hundred twelve million, one hundred thirteen thousand, seven".
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