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14531225054051 is a prime number
BaseRepresentation
bin1101001101110101000010…
…0000011110101101100011
31220110011122001120202121102
43103131100200132231203
53401034422103212201
650523315211345015
73026563205663066
oct323352040365543
956404561522542
1014531225054051
1146a2726795382
1217682b9a5216b
1381539a1c0c64
1438345a6ac8dd
151a2ecce9426b
hexd375081eb63

14531225054051 has 2 divisors, whose sum is σ = 14531225054052. Its totient is φ = 14531225054050.

The previous prime is 14531225054023. The next prime is 14531225054063. The reversal of 14531225054051 is 15045052213541.

14531225054051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14531225054051 - 210 = 14531225053027 is a prime.

It is a super-2 number, since 2×145312250540512 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14531225053996 and 14531225054014.

It is not a weakly prime, because it can be changed into another prime (14531225054251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265612527025 + 7265612527026.

It is an arithmetic number, because the mean of its divisors is an integer number (7265612527026).

Almost surely, 214531225054051 is an apocalyptic number.

14531225054051 is a deficient number, since it is larger than the sum of its proper divisors (1).

14531225054051 is an equidigital number, since it uses as much as digits as its factorization.

14531225054051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 14531225054051 its reverse (15045052213541), we get a palindrome (29576277267592).

The spelling of 14531225054051 in words is "fourteen trillion, five hundred thirty-one billion, two hundred twenty-five million, fifty-four thousand, fifty-one".