Base | Representation |
---|---|
bin | 1101001101110101000010… |
… | …0000011110110000101011 |
3 | 1220110011122001120202212211 |
4 | 3103131100200132300223 |
5 | 3401034422103214001 |
6 | 50523315211345551 |
7 | 3026563205663503 |
oct | 323352040366053 |
9 | 56404561522784 |
10 | 14531225054251 |
11 | 46a2726795544 |
12 | 17682b9a522b7 |
13 | 81539a1c1089 |
14 | 38345a6aca03 |
15 | 1a2ecce94351 |
hex | d375081ec2b |
14531225054251 has 2 divisors, whose sum is σ = 14531225054252. Its totient is φ = 14531225054250.
The previous prime is 14531225054233. The next prime is 14531225054279. The reversal of 14531225054251 is 15245052213541.
It is a weak prime.
It is an emirp because it is prime and its reverse (15245052213541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14531225054251 - 215 = 14531225021483 is a prime.
It is a super-2 number, since 2×145312250542512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14531225054051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265612527125 + 7265612527126.
It is an arithmetic number, because the mean of its divisors is an integer number (7265612527126).
Almost surely, 214531225054251 is an apocalyptic number.
14531225054251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14531225054251 is an equidigital number, since it uses as much as digits as its factorization.
14531225054251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 14531225054251 its reverse (15245052213541), we get a palindrome (29776277267792).
The spelling of 14531225054251 in words is "fourteen trillion, five hundred thirty-one billion, two hundred twenty-five million, fifty-four thousand, two hundred fifty-one".
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