Base | Representation |
---|---|
bin | 10001010100101… |
… | …00101010110111 |
3 | 101010102122012012 |
4 | 20222110222313 |
5 | 244144444224 |
6 | 22230314435 |
7 | 3413064266 |
oct | 1052245267 |
9 | 333378165 |
10 | 145312439 |
11 | 75030428 |
12 | 407b8a1b |
13 | 2414a3bc |
14 | 154285dd |
15 | cb5580e |
hex | 8a94ab7 |
145312439 has 2 divisors, whose sum is σ = 145312440. Its totient is φ = 145312438.
The previous prime is 145312423. The next prime is 145312451. The reversal of 145312439 is 934213541.
145312439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (934213541) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 145312439 - 24 = 145312423 is a prime.
It is a super-2 number, since 2×1453124392 = 42231409856257442, which contains 22 as substring.
It is a Sophie Germain prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145392439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72656219 + 72656220.
It is an arithmetic number, because the mean of its divisors is an integer number (72656220).
Almost surely, 2145312439 is an apocalyptic number.
145312439 is a deficient number, since it is larger than the sum of its proper divisors (1).
145312439 is an equidigital number, since it uses as much as digits as its factorization.
145312439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 32.
The square root of 145312439 is about 12054.5609210788. The cubic root of 145312439 is about 525.7358558000.
The spelling of 145312439 in words is "one hundred forty-five million, three hundred twelve thousand, four hundred thirty-nine".
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