Base | Representation |
---|---|
bin | 11011000100010001… |
… | …00101101010000111 |
3 | 1101111201020120012220 |
4 | 31202020211222013 |
5 | 214230004223310 |
6 | 10401532343423 |
7 | 1023046120521 |
oct | 154210455207 |
9 | 41451216186 |
10 | 14531320455 |
11 | 6187608153 |
12 | 2996614b73 |
13 | 14a770bc92 |
14 | 9bbca2a11 |
15 | 5a0ad6670 |
hex | 362225a87 |
14531320455 has 32 divisors (see below), whose sum is σ = 23817404160. Its totient is φ = 7561344000.
The previous prime is 14531320451. The next prime is 14531320459. The reversal of 14531320455 is 55402313541.
It is an interprime number because it is at equal distance from previous prime (14531320451) and next prime (14531320459).
It is not a de Polignac number, because 14531320455 - 22 = 14531320451 is a prime.
It is a super-2 number, since 2×145313204552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14531320451) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 587080 + ... + 611330.
It is an arithmetic number, because the mean of its divisors is an integer number (744293880).
Almost surely, 214531320455 is an apocalyptic number.
14531320455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14531320455 is a deficient number, since it is larger than the sum of its proper divisors (9286083705).
14531320455 is a wasteful number, since it uses less digits than its factorization.
14531320455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25231.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 14531320455 its reverse (55402313541), we get a palindrome (69933633996).
The spelling of 14531320455 in words is "fourteen billion, five hundred thirty-one million, three hundred twenty thousand, four hundred fifty-five".
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