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14531503153 is a prime number
BaseRepresentation
bin11011000100010010…
…10010010000110001
31101111201120211211111
431202021102100301
5214230031100103
610401540313321
71023050511256
oct154211222061
941451524744
1014531503153
116187722442
1229966a2841
1314a777419b
149bbd0d42d
155a0b2086d
hex362252431

14531503153 has 2 divisors, whose sum is σ = 14531503154. Its totient is φ = 14531503152.

The previous prime is 14531503139. The next prime is 14531503159. The reversal of 14531503153 is 35130513541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14529168369 + 2334784 = 120537^2 + 1528^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14531503153 is a prime.

It is a super-2 number, since 2×145315031532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14531503159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265751576 + 7265751577.

It is an arithmetic number, because the mean of its divisors is an integer number (7265751577).

Almost surely, 214531503153 is an apocalyptic number.

It is an amenable number.

14531503153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14531503153 is an equidigital number, since it uses as much as digits as its factorization.

14531503153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 14531503153 in words is "fourteen billion, five hundred thirty-one million, five hundred three thousand, one hundred fifty-three".