Base | Representation |
---|---|
bin | 11011000100010010… |
… | …10110011001101001 |
3 | 1101111201121201002100 |
4 | 31202021112121221 |
5 | 214230032120410 |
6 | 10401540524013 |
7 | 1023050611554 |
oct | 154211263151 |
9 | 41451551070 |
10 | 14531520105 |
11 | 6187734153 |
12 | 29966b0609 |
13 | 14a777bb0b |
14 | 9bbd1569b |
15 | 5a0b258c0 |
hex | 362256669 |
14531520105 has 24 divisors (see below), whose sum is σ = 25196378688. Its totient is φ = 7747556256.
The previous prime is 14531520097. The next prime is 14531520163. The reversal of 14531520105 is 50102513541.
14531520105 is a `hidden beast` number, since 1 + 4 + 5 + 31 + 520 + 105 = 666.
It is not a de Polignac number, because 14531520105 - 23 = 14531520097 is a prime.
It is a super-3 number, since 3×145315201053 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 86364 + ... + 191106.
It is an arithmetic number, because the mean of its divisors is an integer number (1049849112).
Almost surely, 214531520105 is an apocalyptic number.
14531520105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14531520105 is a deficient number, since it is larger than the sum of its proper divisors (10664858583).
14531520105 is a wasteful number, since it uses less digits than its factorization.
14531520105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107837 (or 107834 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
The spelling of 14531520105 in words is "fourteen billion, five hundred thirty-one million, five hundred twenty thousand, one hundred five".
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