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14531541341 is a prime number
BaseRepresentation
bin11011000100010010…
…11011100101011101
31101111201122210012212
431202021123211131
5214230033310331
610401541210205
71023051030512
oct154211334535
941451583185
1014531541341
1161877490a9
122996700965
1314a7788695
149bbd1d309
155a0b2bd2b
hex36225b95d

14531541341 has 2 divisors, whose sum is σ = 14531541342. Its totient is φ = 14531541340.

The previous prime is 14531541301. The next prime is 14531541371. The reversal of 14531541341 is 14314513541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12900189241 + 1631352100 = 113579^2 + 40390^2 .

It is an emirp because it is prime and its reverse (14314513541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14531541341 - 230 = 13457799517 is a prime.

It is a super-2 number, since 2×145315413412 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14531541298 and 14531541307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14531541301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7265770670 + 7265770671.

It is an arithmetic number, because the mean of its divisors is an integer number (7265770671).

Almost surely, 214531541341 is an apocalyptic number.

It is an amenable number.

14531541341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14531541341 is an equidigital number, since it uses as much as digits as its factorization.

14531541341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 32.

The spelling of 14531541341 in words is "fourteen billion, five hundred thirty-one million, five hundred forty-one thousand, three hundred forty-one".