Base | Representation |
---|---|
bin | 1000011101010111000… |
… | …0100111101110110111 |
3 | 111220002121121201120002 |
4 | 2013111300213232313 |
5 | 4340103433312211 |
6 | 150431552301515 |
7 | 13333112301431 |
oct | 2072560475667 |
9 | 456077551502 |
10 | 145320213431 |
11 | 566a2521248 |
12 | 241b754189b |
13 | 1091bb77c93 |
14 | 7068045651 |
15 | 3ba7d2b03b |
hex | 21d5c27bb7 |
145320213431 has 2 divisors, whose sum is σ = 145320213432. Its totient is φ = 145320213430.
The previous prime is 145320213391. The next prime is 145320213449. The reversal of 145320213431 is 134312023541.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 145320213431 - 226 = 145253104567 is a prime.
It is a super-2 number, since 2×1453202134312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 145320213394 and 145320213403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (145320213461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72660106715 + 72660106716.
It is an arithmetic number, because the mean of its divisors is an integer number (72660106716).
Almost surely, 2145320213431 is an apocalyptic number.
145320213431 is a deficient number, since it is larger than the sum of its proper divisors (1).
145320213431 is an equidigital number, since it uses as much as digits as its factorization.
145320213431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 145320213431 its reverse (134312023541), we get a palindrome (279632236972).
The spelling of 145320213431 in words is "one hundred forty-five billion, three hundred twenty million, two hundred thirteen thousand, four hundred thirty-one".
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