1453213310441 has 2 divisors, whose sum is σ = 1453213310442. Its totient is φ = 1453213310440.

The previous prime is 1453213310359. The next prime is 1453213310443. The reversal of 1453213310441 is 1440133123541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1448087323225 + 5125987216 = 1203365^2 + 71596^2 .

It is a cyclic number.

It is not a de Polignac number, because 1453213310441 - 2³⁴ = 1436033441257 is a prime.

It is a super-2 number, since 2×1453213310441² (a number of 25 digits) contains 22 as substring.

Together with 1453213310443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1453213310398 and 1453213310407.

It is not a weakly prime, because it can be changed into another prime (1453213310443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726606655220 + 726606655221.

It is an arithmetic number, because the mean of its divisors is an integer number (726606655221).

Almost surely, 2^{1453213310441} is an apocalyptic number.

It is an amenable number.

1453213310441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453213310441 is an equidigital number, since it uses as much as digits as its factorization.

1453213310441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1453213310441 its reverse (1440133123541), we get a palindrome (2893346433982).

The spelling of 1453213310441 in words is "one trillion, four hundred fifty-three billion, two hundred thirteen million, three hundred ten thousand, four hundred forty-one".