Search a number
-
+
14532250051 = 111321113641
BaseRepresentation
bin11011000100011000…
…01000100111000011
31101111202222210101101
431202030020213003
5214230224000201
610402004315231
71023060041644
oct154214104703
941452883341
1014532250051
116188092610
1229969a2b17
1314a7976137
149bc0656cb
155a0c1bd01
hex3623089c3

14532250051 has 4 divisors (see below), whose sum is σ = 15853363704. Its totient is φ = 13211136400.

The previous prime is 14532250049. The next prime is 14532250093. The reversal of 14532250051 is 15005223541.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14532250051 - 21 = 14532250049 is a prime.

It is a super-2 number, since 2×145322500512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14532250951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660556810 + ... + 660556831.

It is an arithmetic number, because the mean of its divisors is an integer number (3963340926).

Almost surely, 214532250051 is an apocalyptic number.

14532250051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

14532250051 is a deficient number, since it is larger than the sum of its proper divisors (1321113653).

14532250051 is a wasteful number, since it uses less digits than its factorization.

14532250051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1321113652.

The product of its (nonzero) digits is 6000, while the sum is 28.

Adding to 14532250051 its reverse (15005223541), we get a palindrome (29537473592).

The spelling of 14532250051 in words is "fourteen billion, five hundred thirty-two million, two hundred fifty thousand, fifty-one".

Divisors: 1 11 1321113641 14532250051