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14532654463141 = 54371267286871
BaseRepresentation
bin1101001101111010010110…
…1101001111100010100101
31220110022022200021021020211
43103132211231033202211
53401100334020310031
650524113112455421
73026643503523403
oct323364555174245
956408280237224
1014532654463141
1146a329a640601
1217686386aa571
13815567398759
14383554478473
151a30636e7bb1
hexd37a5b4f8a5

14532654463141 has 4 divisors (see below), whose sum is σ = 14532921804384. Its totient is φ = 14532387121900.

The previous prime is 14532654463087. The next prime is 14532654463163. The reversal of 14532654463141 is 14136445623541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14532654463141 - 221 = 14532652365989 is a prime.

It is a super-2 number, since 2×145326544631412 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14532654463181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133589065 + ... + 133697806.

It is an arithmetic number, because the mean of its divisors is an integer number (3633230451096).

Almost surely, 214532654463141 is an apocalyptic number.

It is an amenable number.

14532654463141 is a deficient number, since it is larger than the sum of its proper divisors (267341243).

14532654463141 is an equidigital number, since it uses as much as digits as its factorization.

14532654463141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267341242.

The product of its digits is 4147200, while the sum is 49.

The spelling of 14532654463141 in words is "fourteen trillion, five hundred thirty-two billion, six hundred fifty-four million, four hundred sixty-three thousand, one hundred forty-one".

Divisors: 1 54371 267286871 14532654463141