1453351339409 has 2 divisors, whose sum is σ = 1453351339410. Its totient is φ = 1453351339408.

The previous prime is 1453351339399. The next prime is 1453351339411. The reversal of 1453351339409 is 9049331533541.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1296136710400 + 157214629009 = 1138480^2 + 396503^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1453351339409 is a prime.

It is a super-2 number, since 2×1453351339409² (a number of 25 digits) contains 22 as substring.

Together with 1453351339411, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1453351339109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726675669704 + 726675669705.

It is an arithmetic number, because the mean of its divisors is an integer number (726675669705).

Almost surely, 2^{1453351339409} is an apocalyptic number.

It is an amenable number.

1453351339409 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453351339409 is an equidigital number, since it uses as much as digits as its factorization.

1453351339409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2624400, while the sum is 50.

The spelling of 1453351339409 in words is "one trillion, four hundred fifty-three billion, three hundred fifty-one million, three hundred thirty-nine thousand, four hundred nine".