1453351340433 has 8 divisors (see below), whose sum is σ = 1946118534048. Its totient is φ = 964742520224.

The previous prime is 1453351340377. The next prime is 1453351340437. The reversal of 1453351340433 is 3340431533541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1453351340433 - 2¹⁰ = 1453351339409 is a prime.

It is a super-2 number, since 2×1453351340433² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1453351340391 and 1453351340400.

It is not an unprimeable number, because it can be changed into a prime (1453351340437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1039592535 + ... + 1039593932.

It is an arithmetic number, because the mean of its divisors is an integer number (243264816756).

Almost surely, 2^{1453351340433} is an apocalyptic number.

It is an amenable number.

1453351340433 is a deficient number, since it is larger than the sum of its proper divisors (492767193615).

1453351340433 is a wasteful number, since it uses less digits than its factorization.

1453351340433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2079186703.

The product of its (nonzero) digits is 388800, while the sum is 39.

Adding to 1453351340433 its reverse (3340431533541), we get a palindrome (4793782873974).

The spelling of 1453351340433 in words is "one trillion, four hundred fifty-three billion, three hundred fifty-one million, three hundred forty thousand, four hundred thirty-three".