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14534341111 = 109816116339
BaseRepresentation
bin11011000100101000…
…00111000111110111
31101111220221000210001
431202110013013313
5214231242403421
610402121212131
71023113601223
oct154224070767
941456830701
1014534341111
116189290664
122997631047
1314a8228b54
149bc44b783
155a0ed1691
hex3625071f7

14534341111 has 8 divisors (see below), whose sum is σ = 14670378800. Its totient is φ = 14398352640.

The previous prime is 14534341091. The next prime is 14534341117. The reversal of 14534341111 is 11114343541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14534341111 - 221 = 14532243959 is a prime.

It is a super-2 number, since 2×145343411112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14534341111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14534341117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 881380 + ... + 897718.

It is an arithmetic number, because the mean of its divisors is an integer number (1833797350).

Almost surely, 214534341111 is an apocalyptic number.

14534341111 is a deficient number, since it is larger than the sum of its proper divisors (136037689).

14534341111 is a wasteful number, since it uses less digits than its factorization.

14534341111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24609.

The product of its digits is 2880, while the sum is 28.

Adding to 14534341111 its reverse (11114343541), we get a palindrome (25648684652).

The spelling of 14534341111 in words is "fourteen billion, five hundred thirty-four million, three hundred forty-one thousand, one hundred eleven".

Divisors: 1 109 8161 16339 889549 1780951 133342579 14534341111