14534380438 has 4 divisors (see below), whose sum is σ = 21801570660. Its totient is φ = 7267190218.

The previous prime is 14534380433. The next prime is 14534380447. The reversal of 14534380438 is 83408343541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 83408343541 = 89519 ⋅931739.

It is a super-3 number, since 3×14534380438³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14534380394 and 14534380403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14534380433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3633595108 + ... + 3633595111.

It is an arithmetic number, because the mean of its divisors is an integer number (5450392665).

Almost surely, 2^14534380438 is an apocalyptic number.

14534380438 is a deficient number, since it is larger than the sum of its proper divisors (7267190222).

14534380438 is an equidigital number, since it uses as much as digits as its factorization.

14534380438 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7267190221.

The product of its (nonzero) digits is 552960, while the sum is 43.

The spelling of 14534380438 in words is "fourteen billion, five hundred thirty-four million, three hundred eighty thousand, four hundred thirty-eight".