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145344331355 = 5291002374699
BaseRepresentation
bin1000011101011100110…
…0100111111001011011
3111220011022000001010112
42013113030213321123
54340131122100410
6150434213234535
713333524301166
oct2072714477133
9456138001115
10145344331355
11567050a4413
1224203632a4b
1310923b70842
14706b322add
153ba9ee2105
hex21d7327e5b

145344331355 has 8 divisors (see below), whose sum is σ = 180427446000. Its totient is φ = 112265966176.

The previous prime is 145344331351. The next prime is 145344331361. The reversal of 145344331355 is 553133443541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145344331355 - 22 = 145344331351 is a prime.

It is a super-2 number, since 2×1453443313552 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (145344331351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 501187205 + ... + 501187494.

It is an arithmetic number, because the mean of its divisors is an integer number (22553430750).

Almost surely, 2145344331355 is an apocalyptic number.

145344331355 is a deficient number, since it is larger than the sum of its proper divisors (35083114645).

145344331355 is a wasteful number, since it uses less digits than its factorization.

145344331355 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1002374733.

The product of its digits is 648000, while the sum is 41.

Adding to 145344331355 its reverse (553133443541), we get a palindrome (698477774896).

The spelling of 145344331355 in words is "one hundred forty-five billion, three hundred forty-four million, three hundred thirty-one thousand, three hundred fifty-five".

Divisors: 1 5 29 145 1002374699 5011873495 29068866271 145344331355